Question

if third term of AP is 16 and 7th term exceeds the 5th term by 12 then find AP

Answer 1

Answer:

4, 10, 16, 22, 28, 34...

Step-by-step explanation:

a7 = a5 + 12

⇒ a + 6d = a + 4d + 12

⇒ 2d = 12

⇒ d = 6

a3 = 16

⇒ a + 2d = 16

⇒ a + 2(6) = 16

⇒ a = 16 - 12 = 4

∴ The AP obtained is 4, 10, 16, 22...

Answer 2

Hey mate!

It is given that,
a3 = 16; a7 = a5+12
Now,
a3 = a+(3-1)d
=>16 = a+2d
=>a = 16-2d ...(i)
Also,
a7 = a5+12
=>a+6d = a+4d+12
=>2d = 12
=>d = 6 ...(ii)
Substituting (ii) in (i),
a = 16-2(6)
=>a = 16-12
=>a = 4
Hence, the AP is 4, 10, 16, ...

That's the answer!

Hope it helps :)

I'm sorry for answering late - net slow.