Question

if thita is an acute angle and tan thita is 8/15 find the value of sec thita +cosec thita​

Answer 1

Tan thita 8/15

tan thita=p/b

let the variable be X

p=8k,b=15k

by Pythagoreans theorem

p^2+b^2=h^2

(8k)^2+(15k)^2=h^2

64k^2+225k^2=h^2

h=17k

Sec thita=h/b=17k/15k=17/15

cosec thita=h/p=17k/8k=17/8

sec thita + cosec thita =17/15+17/8

17*8+17*15/120

136+255/120=391/120

HOPE THIS HELPS!!