Question

If three angles of a triangle are 2x+10 ,3x-10 and 4x-18.the smallest angle will be?

​

Answer 1

$\Large{\underline{\underline{\mathfrak{\red{\bf{Solution}}}}}}$

$\Large{\underline{\mathfrak{\orange{\bf{Given}}}}}$

• Three angles of triangle = (2x + 10) , (3x - 10) , (4x - 18)

$\Large{\underline{\mathfrak{\orange{\bf{Find}}}}}$

• Smallest Angle of triangle

$\Large{\underline{\underline{\mathfrak{\red{\bf{Explanation}}}}}}$

We know,

$\small\boxed{\boxed{\tt{\green{\:Sum\:of\:all\:angle\:of\:triangle\:=\:180}}}}$

So,

➩ Sum of angles = 180°

➩ (2x + 10) + (3x - 10) + (4x - 18) = 180

➩ (2x + 3x + 4x ) + (10 - 10 - 18) = 180

➩ 9x - 18 = 180

➩ 9x = 180 + 18

➩ 9x = 198

➩ x = 198/9

➩ x = 22

Now, Calculate All Angle of triangle

➩ First angle be (2x + 10) = (2×22 + 10) = (44+10) = 54°

➩ Second Angle be (3x - 10) = (3*22-10) = (66-10) = 56°

➩ Third Angle be (4x - 18) = (4*22-18) = (88-18) = 70°

$\Large{\underline{\underline{\mathfrak{\red{\bf{Hence}}}}}}$

• Smallest Angle will be = 54 °

___________________

Answer 2

Pls mark as brainliest answer