Question

If three dice are thrown simultaneously, find the probability of getting a sum of
at least 5​

Answer 1

Three dice thrown total events would be 6 X 6 X 6 = 216

Number of events of getting a total of 5 = 6

i.e. (1, 1, 3), (1, 3, 1), (3, 1, 1), (2, 2, 1), (2, 1, 2) and (1, 2, 2)

Therefore, probability of getting a total of 5

              Number of favorable outcomes

P(E1) =     Total number of possible outcome

     = 6/216

     = 1/36

Answer 2

Answer:

1/3

yes it is correct answer