Question

If three taps are opened together, a tank is filled in 12 hours. one of the taps can fill it in 10 hours and another in 15 hours. how does the third tap work

Answer 1

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Answer 2

Answer:empty the tank in 12 hours

Step-by-step explanation:

as given first and second pipe can fill hte tank in 10 nad 15 hours.

unit work of pipe A = 1/ 10 hours

unit work of pipe B = 1/ 15 hours

let pipe C will fill the tank in x hours.

so unit work of pipe C = 1/ x hours

as all the pe can fill the tank in 12 hours

unit work of all the pipe = 1/ x hours

so

$\frac{1}{10}+\frac{1}{15}+\frac{1}{x}=\frac{1}{12}\\\\\frac{1}{x}=\frac{1}{12}-\frac{1}{10}-\frac{1}{15}\\\\\frac{1}{x}=\frac{5-6-4}{60}\\\\\frac{1}{x}=\frac{-5}{60}\\\\\frac{1}{x}=\frac{-1}{12}$

as value is negative it means third pipe empty the tank in 12 hours.