If triangle ABC ~ PQR, h1 and h2 are the heights of triangle ABC and PQR respectively.
AB : PQ = 4:9 and h2 = 13.5cm,
then the value of h1 is
6 cm
4.8 cm
12 cm
10 cm
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Given : ΔABC ~ ΔPQR , h1 and h2 are the heights of triangle ABC and PQR respectively. AB : PQ = 4:9 and h2 = 13.5cm
To find : value of h1
Solution:
in Similar triangle ratio of corresponding sides = ratio of corresponding height
ΔABC ~ ΔPQR
=> AB / PQ = h1 / h2
AB/PQ = 4/9
h2 = 13.5 cm
=> 4/9 = h1/ 13.5
=> 4 * 13.5 / 9 = h1
=> 54 / 9 = h1
=> 6 = h1
=> h1 = 6 cm
value of h1 is 6 cm
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