if two adjacent angles of a parellelogram PQRS are (10y-9)° & (8y+45°), Find all the four angles of parallelogram.
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Answered by
2
We know that,
Adjacent angles of paralellogram are suplementry
So,
10y - 9 + 8y + 45 = 180
=> 18y + 36 = 180
=> 18 y = 144
=> y = 8
First angle = 71°
Second angle = 109°
Third angle = 71°
Fourth angle = 109°
Adjacent angles of paralellogram are suplementry
So,
10y - 9 + 8y + 45 = 180
=> 18y + 36 = 180
=> 18 y = 144
=> y = 8
First angle = 71°
Second angle = 109°
Third angle = 71°
Fourth angle = 109°
Answered by
1
adjacent angles=180degree(property of parallelogram)
so,
10y-9+8y+45=180
18y+36=180
18y=180-36
18y=144
y=144/18
=8
so angles after putting values of y=71 and 109
so angles =71,71,109,109(opposite angles are equal)
so,
10y-9+8y+45=180
18y+36=180
18y=180-36
18y=144
y=144/18
=8
so angles after putting values of y=71 and 109
so angles =71,71,109,109(opposite angles are equal)
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