Question

If two bodies of different masses m1 and m2 are dropped from two different heights a and bin Vaccum , give the ratio of time taken by the two bodies to drop through these distance?

Answer 1

HEY;_

For a freely falling object :

a=g;

Initial velocity=u=0 m/s

g=9.8m/s²

from second equation of motion:S=ut+1/2 at²

for First object we get :

h1= gT1²/2

⇒T1=√2h1/g

For second object we get h2=gT2²/2

⇒T2=√2h2/g

T1/T2 =√h1/h2

But here h1= a and h2 =b

so, T1/T2=√a/b

Answer 2

Answer: The ratio would be 1 : 1

Explanation: This is because when two objects of any masses are dropped in vacuum, no gravitational force , or any other force acts on the body. As a result both the objects fall with same velocity, irrespective of the masses.

Hope this helps