If two boxes of mass ratio 2:1 are kept on a rough surface. Friction force acting on them will be
4 points
A) In ratio of 2:1
B) Will be zero for both
C) Can’t say anything due to inadequate information
D) Will depend on roughness of surface
Answers
Answer:
Hi friend!
Explanation:
The object is both in translational and rotational equilibrium
Since the object is at rest, we can infer that applied force = frictional force and hence the friction is static friction and hence translational equilibrium is achieved
If we consider the torque about the Centre of mass of the object, both the forces will produce a torque in the clockwise direction. Hence the object should rotate. But this torque is balanced by an equal and opposite torque by the normal force.
Initially the normal force acts through the centre of the object, but as the force is applied, the normal force starts shifting towards right and hence a torque equal to normal force x distance between the point to which it has shifted from the CG will exist. The sum of these two torques will be zero. Thus rotational equilibrium is also achieved
Answer:
The answer is a option A