the equation of line parallel to 5x+12y=1 and at a distance of 3 units from (1,0) is
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The equation ns of the lines parallel to 5x−12y+26=0 and at a distance of 4 units from it are: 5x−12y−26=0 5x−12y+26=0 5x−12y−78=0 (d) 5x−12y+78=0
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