if two intersecting chords of a circle make equal angles witb diameter of the circle passing through the point of intersection of the chords prove chords ard equal?
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heey friend here is your answer
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jiya2422:
thanx alot dear
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Heya mate,
here is your answer,
In this figure AB and CD are two chords intersect at point P. O is the centre of the circle. XY is the diameter of the circle passes through point P.
Given that ∠OPM = ∠OPN
Let OM⊥AB and ON⊥CD
In ∆OMP and ∆ONP
∠OMP = ∠ONP (Each 90°)
∠OPM = ∠OPN (Given)
OP = OP (Common)
∴ ∆OMP ≅ ∆ONP (AAS congruence criterion)
⇒ OM = ON (C.P.C.T)
Since the chords AB and CD are equidistant from the centre of the circle so, the chords AB and CD are equal
∴AB = CD
Hope this helps
if you have any further doubt or want any help you can ask me. i would like to help.
Thank you
#Sneha
here is your answer,
In this figure AB and CD are two chords intersect at point P. O is the centre of the circle. XY is the diameter of the circle passes through point P.
Given that ∠OPM = ∠OPN
Let OM⊥AB and ON⊥CD
In ∆OMP and ∆ONP
∠OMP = ∠ONP (Each 90°)
∠OPM = ∠OPN (Given)
OP = OP (Common)
∴ ∆OMP ≅ ∆ONP (AAS congruence criterion)
⇒ OM = ON (C.P.C.T)
Since the chords AB and CD are equidistant from the centre of the circle so, the chords AB and CD are equal
∴AB = CD
Hope this helps
if you have any further doubt or want any help you can ask me. i would like to help.
Thank you
#Sneha
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