Question

if two metals X and Y from the salts x s o4 and white 2 S o4 respectively the solution of salt x s o4 is blue in colour whereas that of white 2 S o4 is colourless when warium carbonate solution is added to Excess of 4 solution then a white precipitate is formed along with the salt which has the solution green and when Barium Chloride solution is added to y 2 S o4 solution then the same white precipitate Z is formed along with colourless common solution what could be the metals for X and Y we write the name of formula of salt Access for write the name and formula of salt by 2 S o4 write the name and formula of white precipitate Z write the name and formula of the salt which turns the sodium sorry solution green in first case​

Answer 1

XSO⁴ is blue in colour. As we know that CuSO⁴ is blue in color, we can infer that X is Cu.

Now, Y²SO⁴ is colorless, from this we can infer that it would probably be an alkali metal.

Now, BaCl² is added to these salts, a white ppt is formed which would probably be BaSO⁴ (White in color). Now When XSO⁴ and CuSO⁴ react with BaCl² two salts XCl² and YCl are formed respectively.

Now we know that XCl² is green in color, which is a property of CuCl². This further consolidates that X is Cu.

We also know that YCl is colorless common salt solution this we can conclude that YCl is NaCl and Y is Na.

Answers:-

a) X- Cu and Y- Na

b) XSO⁴ - CuSO⁴- Copper sulphate

c) Y²SO⁴ - Na²SO⁴ - sodium sulphate

d) Z- BaSO⁴- Barium Sulphate

e) Copper chloride - CuCl²

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