Math, asked by jyasomejya, 1 year ago

If two positive integers p and q are written as p=a2b3 and q=a2b and a and b are prime no and verify when lcmpq×hcf of p.q. =p.q

Answers

Answered by Mackmaan
52
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Answered by nikitasingh79
32

HCF of two or more numbers is the product of the smallest power of each common prime factors involved in the numbers.

LCM of two or more numbers is a product of the greatest power of its prime factors involved in the numbers with highest power.


SOLUTION:

Given:

p = a²b³

q= a²b

HCF(p,q)= a²b

LCM (p,q)= a²b³

HCF× LCM= a²b× a²b³= a⁴b⁴

HCF× LCM=a⁴b⁴...........(1)

p ×q= a²b³× a²b= a⁴b⁴

p ×q= = a⁴b⁴..................(2)

Lcm (p,q) × Hcf(p,q) = pq

a⁴b⁴ = a⁴b⁴
[From equation 1 and 2]

Verified,..

HOPE THIS WILL HELP YOU....
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