If two positive integers p and q are written as p=a2b3 and q=a2b and a and b are prime no and verify when lcmpq×hcf of p.q. =p.q
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HCF of two or more numbers is the product of the smallest power of each common prime factors involved in the numbers.
LCM of two or more numbers is a product of the greatest power of its prime factors involved in the numbers with highest power.
SOLUTION:
Given:
p = a²b³
q= a²b
HCF(p,q)= a²b
LCM (p,q)= a²b³
HCF× LCM= a²b× a²b³= a⁴b⁴
HCF× LCM=a⁴b⁴...........(1)
p ×q= a²b³× a²b= a⁴b⁴
p ×q= = a⁴b⁴..................(2)
Lcm (p,q) × Hcf(p,q) = pq
a⁴b⁴ = a⁴b⁴
[From equation 1 and 2]
Verified,..
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