Question

if two resistors R1 = 10 ohm and R2 = 40 ohm are connected in parallel in a circuit of 12 v battery it then what will be the equivalent resistance of the circuit? Find the heat evolve if the circuit runs from 30 minutes​

Answer 1

Answer:

Here's your answer mate!!!

Answer 2

The heat evolve if the circuit runs from 30 minutes​ is 32400 Joules.

Explanation:

Resistance 1, $R_1=10\ \Omega$

Resistance 2, $R_2=40\ \Omega$

Both resistors are connected in parallel. The equivalent resistance is given by :

$\dfrac{1}{R}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

$\dfrac{1}{R}=\dfrac{1}{10}+\dfrac{1}{40}$

R = 8 ohms

Voltage of battery, V = 12 V

The heat evolve if the circuit runs from 30 minutes​ or 1800 seconds. It is given by :

$H=\dfrac{V^2t}{R}$

$H=\dfrac{(12)^2\times 1800}{8}$

H = 32400 Joules

So, the heat evolve if the circuit runs from 30 minutes​ is 32400 Joules. Hence, this is the required solution.

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Ohm's law

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