Math, asked by rekhasuri31, 1 year ago

if two tangents TP and TQare drawn to a circle with centre O from an external point T ...where angle PTQ is 100 deg .find angle POQ

Answers

Answered by fanbruhh
0

.
 \huge{hey}



.
 \huge{ \mathfrak{here \: is \: answer}}




.
 \bf{given}



.
 \sf{figure \: is \: in \: pic}


a circle with center o.

Tp and TQ are tangent at point t and p respectively .

.
 \angle{ptq} = 100 \degree




.
 \bf{to \: find}


.
 \sf{ \angle{poq}}




in figure

.
 \sf{ \angle{ptq} = 100 \degree}




op and oq is radius of circle

and radius meet at tangent making angle at 90°.

hence op=oq

hence

op=oq=90°

we know that

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 \angle{ptq}  +  \angle{tpq} +  \angle{tqp} +  \angle{poq} = 360 \degree




hence

90°+90°+100°+angle poq=360°

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  280 \degree   +  \angle{poq} = 360 \degree



.
 \sf{ \angle{poq} = 360 \degree - 280 \degree}





.
 \bf{hence \angle{poq} = 80 \degree}




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 \huge \boxed{hope \: it \: helps}



.

 \huge{ \mathbb{THANKS}}



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