if two thirds of a rational number exceeds it's three fifths by 7/3 find the rational number
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Hii....☺
Here is your solution....☺
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→ Let the rational number be "x"
According to question we have,
→ 2/3 of x = 3/5 of x + 7/3
→ 2x/3 = 3x/5 + 7/3
→ 2x/3 - 3x/5 = 7/3
→ 10x - 9x / 15 = 7/3
→ x/15 = 7/3
→ 3x = 7 × 15
→ x = 7 × 15 / 3
→ x = 35
Hence, the required rational number = 35.
Hope this helps you...☺
Thanks....☺
Here is your solution....☺
================================
→ Let the rational number be "x"
According to question we have,
→ 2/3 of x = 3/5 of x + 7/3
→ 2x/3 = 3x/5 + 7/3
→ 2x/3 - 3x/5 = 7/3
→ 10x - 9x / 15 = 7/3
→ x/15 = 7/3
→ 3x = 7 × 15
→ x = 7 × 15 / 3
→ x = 35
Hence, the required rational number = 35.
Hope this helps you...☺
Thanks....☺
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