If two variables X and Y are related by 2x+3y-7=0 and the mean and mean deviation about mean of X are 1 and 0.3 respectively, then the coefficient of mean deviation of Y about it's mean is?
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37
Answer:
12
Step-by-step explanation:
If two variables x and y are related by 2x+3y-7=0 and the mean and mean deviation about mean of x are 1 and 0.3 respectively then the coefficient of mean deviation of y about its mean is
2x+3y-7=0
=> 3y = 7 - 2x
=> y = 7/3 - 2x/3
Mean of x = 1
Mean of y = 7/3 - 2/3 = 5/3
Mean deviation of x = 0.3
Mean deviation of y = (2/3)*0.3 = 0.2
Coefficient of mean deviation = (Mean Deviation/ Mean) * 100
= (0.2/(5/3) ) * 100
= 60/5
= 12
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