Question

if u really brainly solve this?

Answer 1

150000 is ur answer friend

Answer 2

Hey.

Let the initial weight of the diamond be x

so, price of the diamond is directly proportional to x^2

i.e., price = k x^2

where k is the constant of proportionality

Now the diamond broke

So, 1 : 2 : 3 : 4 is the ratio of the weight of the pieces

Let 10x/10 as the old weight or total weight

i.e., 1x/10 , 2x/10 , 3x/10 & 4x/10 are the new weights

so, new prices will be

p1 = k (1x/10)^2 = k x^2/100

p2 = k (2x/10)^2 = k 4x^2/100

p3 = k (3x/10)^2 = k 9x^2/100

p4 = k (4x/10)^2 = k 16x^2/100

So, total price of the pieces of the diamond

= p1 + p2 + p3 + p4

= k x^2/100 ×{ 1 + 4 + 9 + 16}

= k x^2/100 × 30

= 3 k x^2/10

According to question; there is a loss of rs.7000 after the diamond broke

so, 3 k x^2 /10 + 7000 = k x^2

or, kx^2 - 3kx^2/10 = 7000

or, (10kx^2 - 3 kx^2)/10 = 7000

or, 7 kx^2 /10 = 7000

or, kx^2 = 10000

or, original price of the diamond = kx^2

= rs. 10000

And this is correct answer.

I tried solving by other methods too.

Thanks.