if ur good at physics so plzzz solve this...
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hair the train move from rest that means u is equal to zero acceleration is equal to 0.2 m/s and time is equal to 5 minutes that is 5 into 60 is equal to 300 seconds
so following the second equation
S =ut +1÷2a×t×t
=0×300+2×0.2×300×300
=0+4×9000
=36000m
speed =distance ÷ time
=36000÷300
=120m/s
so following the second equation
S =ut +1÷2a×t×t
=0×300+2×0.2×300×300
=0+4×9000
=36000m
speed =distance ÷ time
=36000÷300
=120m/s
Madhumita11:
thank you very much
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u=0 m/s
a=0.2 m/s^2
t = 5 mins = 300 sec.
v=?
We know, v = u + at
Therefore, v = 0 + (0.2×300)
=> v = 0 + 60
=> v = 60 m/s.
a=0.2 m/s^2
t = 5 mins = 300 sec.
v=?
We know, v = u + at
Therefore, v = 0 + (0.2×300)
=> v = 0 + 60
=> v = 60 m/s.
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