❤️If vectors
A = cos ωt i + sin ωt j and B=cos ωt/2 i+sin ωt/2 j are functions of time, then the value of t at
which they are orthogonal to each other is:
(1) t = 0
(2) t = π/4ω
(3) t = π/2ω
(4) t = π/ω
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(4) t = π/w
step-by-step explanation:
given,
vector A = cos ωt i + sin ωt j
and
vector B = cos ωt/2 i + sin ωt/2 j
Now,
It is given that they are orthogonal
It means they are perpendicular to each other.
It means the dot product will be equal to zero,
as A•B = |A||B| cos 90°
but cos 90° = 0
=> |A||B| = 0
=> (cos ωt i + sin ωt j )•(cos ωt/2 i + sin ωt/2 j)=0
since im dot product only same axis results
=> (cos wt × cos wt/2) + (sin wt × sin wt/2) = 0
further solving the equation,
we get
(4) t = π/w
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