Physics, asked by uxmani2920, 1 year ago

If vectors \vec{A}=\cos\omega t\hat{i}+\sin\omega t\hat{j}\ and\ \vec{B}=\cos \frac{\omega t}{2}\hat{i}+\sin\frac{\omega t}{2}\hat{j} are functions of time, then the value of t at which they are orthogonal to each other is :
(a) t = \frac{\pi}{2\omega}
(b) t = \frac{\pi}{\omega}
(c) t = 0
(d) t = \frac{\pi}{4\omega}

Answers

Answered by Anonymous
1

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If vectors \vec{A}=\cos\omega t\hat{i}+\sin\omega t\hat{j}\ and\ \vec{B}=\cos \frac{\omega t}{2}\hat{i}+\sin\frac{\omega t}{2}\hat{j} are functions of time, then the value of t at which they are orthogonal to each other is :

(a) t = \frac{\pi}{2\omega}

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