The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be(a) 60 m (b) 71 m(c) 100 m (d) 141 m
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option no. c should be the answer
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Explanation:
Horizontal range = 50m
Let the angle of projection be α
Initial velocity = u
Acceleration due to gravity = g
∅1 = 15° and ∅2 = 45°
Thus,
In first case where range = 50
=u²/g(sin² x 15°)
=u²/2g
u²/g = 100
In second case where range = u²/g (sin² x 45°)
= [u²/g ]sin 90
= 100m
Thus, the projectile when fired at an angle of 45°, will have the range of 100m
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