Physics, asked by Zack9058, 1 year ago

The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be(a) 60 m (b) 71 m(c) 100 m (d) 141 m

Answers

Answered by govindsharmazerofour
4

option no. c should be the answer

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Answered by Anonymous
2

Answer:

Explanation:

Horizontal range = 50m

Let the angle of projection be α

Initial velocity = u  

Acceleration due to gravity = g

∅1 = 15° and ∅2 = 45°

Thus,

In first case where range = 50

=u²/g(sin² x 15°)

=u²/2g

u²/g = 100

In second case where range = u²/g (sin² x 45°)

= [u²/g ]sin 90

= 100m

Thus, the projectile when fired at an angle of 45°, will have the range of 100m

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