Question

The x and y coordinates of the particle at any time are x = 5t – 2t² and y = 10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t = 2s is(a) 5 m/s² (b) –4 m/s²(c) –8 m/s²(d) 0

Answer 1

hope you understand this

Answer 2

Answer:

B) –4 m/s²

Explanation:

X = (5t – 2t²) (Given)

y = 10t (Given)

Since, x = (5t – 2t²)m

Thus, velocity dx/dt = (5-4t) m/s

Acceleration = d²X/dt² = - 4 m/s²

Similarly,

y = ( 10t)m

Thus dy/dt = 10m/s

d²y/dt² = 0 m/s²

Thus, the acceleration in Y-direction is zero and acceleration in X-direction is constant. Therefore the acceleration at time t = 2s is -4 m/s2