Question

If wavelength is equal to distance travelled by the electron in one second

Answer 1

Answer:

We know that Planck's constant divided by the momentum gives the wavelength of the particle,

$\lambda \quad =\quad \frac { h }{ p } \quad =\quad \frac { h }{ mv }$

If the distance traveled by the electron in one second, then the above equation changes as,

$\lambda\quad =\quad \frac { h }{ mv } \quad =\quad v\times 1second$

${ v }^{ 2 }\quad =\quad \frac { h }{ m } \times 1second$

Therefore, $v\quad =\quad (\frac { h }{ m } \times 1second)\frac { 1 }{ 2 }$  

By substituting the values of Planck's constant and mass of electron values, we get

$(h\quad =\quad 6.626\times { 10 }^{ -34 }J\frac { sande }{ m } \quad =\quad 9.109\times { 10 }^{ -31 }Kg)$

Therefore $v\quad =\quad (6.626\times { 10 }^{ -34 }Js/9.109\times { 10 }^{ -31 }Kg\times s)\frac { 1 }{ 2 }$

= 0.027m/s

The distance traveled by the electron is 0.027m/s or 2.7cm/s or 0.06mm/hr

Answer 2

Explanation:

Its the correct answer...