In a group of cows and hens the no of legs are 14 more than twice the no of heads the no of cows is
Answers
Answered by
6
Let the number of cows be x and number of hens be y.
Then, total number of legs = 4x + 2y
Total number of heads = x + y
Given, 4x + 2y = 2×(x + y) + 14
4x - 2x = 14
Number of cows, x = 7
Then, total number of legs = 4x + 2y
Total number of heads = x + y
Given, 4x + 2y = 2×(x + y) + 14
4x - 2x = 14
Number of cows, x = 7
Answered by
37
Question :-
In a group of cows and hens the no of legs are 14 more than twice the no of heads the no of cows is..!
Answer :-
→ Number of cows = 7
To Find :-
→ Number of cows .
Explanation :-
Let the number of cows is "a" and number of hens is "b",
We know that a cow has 4 legs and a hen has 2 legs ,
hence ,
total legs = 4a + 2b ,
according to the question,
number of legs are 14 more then twice of number of heads ,
→ 4a + 2b = 2( a + b) + 14
→ 4a + 2b - 2a - 2b = 14
→ 2a = 14
→ a = 7 ,
because
number of heads of 7 cows = 14
hence, number of cows is 7 .
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