Question

If x=1/3-2root2, y=1/3+2root2, prove that xy^2+x^2y=6

Answer 1

Answer:

or x^3 - 8 - 6x(x-2) = 2^2 + 2^1 + 3*[2^{(2/3)+( 1/3)}[2^(2/3)+2^(1/3) ... What is the value of x if 2^x+3^x-4^x + 6^x - 9^x = 1? ... If 1/x+1/y=2 and 1/xy=4, what is the value of (x+y)/2? ·