If x = 1/3-8 and y = 1/3+8 then find the value of x +y+xy
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x = 1/3 -8 ----(1)
y= 1/3 +8 ---(2)
required
x+y +xy
= 1/3 -8 + 1/3 +8 + (1/3 -8) ( 1/3 +8)
= 1/3+1/3 + (1/3)² - 8²
= 2/3 + 1/9 - 64/1
lcm = 9
= (6 +1 - 576)/9
= (-569)/9
y= 1/3 +8 ---(2)
required
x+y +xy
= 1/3 -8 + 1/3 +8 + (1/3 -8) ( 1/3 +8)
= 1/3+1/3 + (1/3)² - 8²
= 2/3 + 1/9 - 64/1
lcm = 9
= (6 +1 - 576)/9
= (-569)/9
mysticd:
u'r welcome
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