Math, asked by criskristabel, 1 month ago

if x=1 and y=2 is a solution of the equation 3x+5y-k=0,then the value of k is?

Answers

Answered by ImperialGladiator
14

Answer:

k = 13

Explanation:

Given equation,

→ 3x + 5y - k = 0

Whose solution is (1, 2).

Then,

  • x = 1
  • y = 2

Substituting the values :-

→ 3x + 5y - k = 0

→ 3(1) + 5(2) - k = 0

→ 3 + 10 - k = 0

→ 13 - k = 0

→ 13 = k

k = 13

The value of k is 13.

_____________________

Quick check:

If k is 13

Then the equation goes like this :-

→ 3x + 5y - 13 = 0

By the solution (1, 2)

→ 3(1) + 5(2) - 13 = 0

→ 3 + 10 - 13 = 0

→ 13 - 13 = 0

→ 0 = 0

Hence, proved

Answered by CopyThat
13

EXPLANATION :-

GIVEN :

  • x = 1 and y = 2 is a solution of the equation 3x + 5y - k = 0.

TO FIND:

  • The value of k.

SOLUTION:

⟹ 3x + 5y - k = 0

⟹ 3(1) + 5(2) - k = 0

⟹ 3 + 10 - k = 0

⟹ 13 - k = 0

⟹ k = 13

∴ The value of k is 13.

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