if x=1 and y=2 is a solution of the equation 3x+5y-k=0,then the value of k is?
Answers
Answered by
14
Answer:
k = 13
Explanation:
Given equation,
→ 3x + 5y - k = 0
Whose solution is (1, 2).
Then,
- x = 1
- y = 2
Substituting the values :-
→ 3x + 5y - k = 0
→ 3(1) + 5(2) - k = 0
→ 3 + 10 - k = 0
→ 13 - k = 0
→ 13 = k
∴ k = 13
The value of ‘k’ is 13.
_____________________
Quick check:
If k is 13
Then the equation goes like this :-
→ 3x + 5y - 13 = 0
By the solution (1, 2)
→ 3(1) + 5(2) - 13 = 0
→ 3 + 10 - 13 = 0
→ 13 - 13 = 0
→ 0 = 0
Hence, proved
Answered by
13
EXPLANATION :-
GIVEN :
- x = 1 and y = 2 is a solution of the equation 3x + 5y - k = 0.
TO FIND:
- The value of k.
SOLUTION:
⟹ 3x + 5y - k = 0
⟹ 3(1) + 5(2) - k = 0
⟹ 3 + 10 - k = 0
⟹ 13 - k = 0
⟹ k = 13
∴ The value of k is 13.
Similar questions