Question

Q. -a²+[a²-4-(3a²+2a²)]
find the value at x= -5,y=2and a=7.
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Answer 1

Answer:

Step-by-step explanation:

Consider the “floor” of the cube. It is a square with the dimensions of a x a.

If we draw a diagonal on this, its’ length would be √(a²+a²), or √2a², or

a√2.

Then, a diagonal going through the midpoint of the cube would be:

D²=a²+a²(√2)²

=a²+2a²

=3a²

Thus, the diagonal would be of length √3a². Or a√3……….