if x=1 is a zero of the polynomial p(x)=27x cube-ax square-x+3
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27 (1)cube-a (1)square -1+3=0
27-a-1+3=0
30-a-1=0
29-a=0
therefore a=29
27-a-1+3=0
30-a-1=0
29-a=0
therefore a=29
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