if x= 1/
![\sqrt{2} \sqrt{2}](https://tex.z-dn.net/?f=+%5Csqrt%7B2%7D+)
,the value of x+1/x is ?
Answers
Answered by
1
Answer:
x = 1/root2
1 + root2 + 1 + root2
2 + 2 root 2
hope it helps
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Answered by
1
Answer:
Hey mate your answer is here..............
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