Math, asked by anamitrachatterjee04, 6 months ago

if x - (1/x)^2=36,find the value of x^2+ 1/x^2​

Answers

Answered by ketan2371
0

Step-by-step explanation:

We know that (x - 1/x)^2 = x^2 + 1/x^2 - 2

Since x^2 + 1/x^2 = 38,

(x - 1/x)^2 = 38 - 2

(x - 1/x)^2 = 36

(x - 1/x) = (36)^(1/2)

x - 1/x = 6 or -6

This is the required answer!

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