Math, asked by dishu2515, 1 year ago

if x+1/x=√5 find the value of x^2+1/x^2​

Answers

Answered by Prakhar2908
1

Answer:

3

Step-by-step explanation:

x+1/x =√5

x²+1/x² = (x+1/x)²-2 = 5-2 = 3

Answered by BrainlyKingdom
0

Answer :

\sf{x^2+\dfrac{1}{x^2}=3}

Step-by-step explanation :

\sf{x+\dfrac{1}{x}=\sqrt{5}}

  • Squaring on Both Sides

\to\sf{\left(x+\dfrac{1}{x}\right)^2=(\sqrt{5})^2}

  • Apply Algebraic Identify : \sf{(a+b)^2=a^2+b^2+2ab}

\to\sf{x^2+\dfrac{1^2}{x^2}+2\times x\times \dfrac{1}{x}=(\sqrt{5})^2}

  • We know \sf{(\sqrt{a})^2=a}

\to\sf{x^2+\dfrac{1}{x^2}+2=5}

  • Subtracting 2 from both Sides

\to\sf{x^2+\dfrac{1}{x^2}+2-2=5-2}

\boxed{\to\sf{x^2+\dfrac{1}{x^2}=3}}

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