If x^2 + 1/4x^2 = 15, find the value of x^3+1/8x^3
Please help me
RahulRJVeer:
easy
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x^2+(1/4)x^2=15
x^2(1+1/4)=15
5/4x^2=15
x^2=15×4/5=3×4=12
x=(12)^1/2
x=2×3^1/2
x^3+1/8x^3
=x^3(1+1/8)
=9/8x^3
=9/8×(2×3^1/2)^3
=9/8×8×3^(1/2×3)
=9×27^1/2
=9×3×3^1/2
=27×3^1/2
Hello there , Rohit , I want to correct something in your answer , you had written x² + (1/4)x² this is the fault because when we solve the bracket the question will become x² + x²/4 , but the question is x² + 1/4x² in which the denominator 4 has x² not the numerator have x² . Hope you understand.
If you want to write 1/4 in bracket then you should write (1/4) x 1/x² .
ok I understood that Thnx
No problem bro
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