Math, asked by ruthika18, 1 year ago

(sin^3A +sin3A/sinA) +(cos^3A-cosA/cosA)=

Answers

Answered by puchkii

first split all the terms..

=(sin³A/sinA )+(sin3A/sinA)+(cos³A/cosA)- (cosA/cosA)

=sin²A + (sin3A /sinA) + cos²A -1

=now.open sin² A as (1-cos²A)

then,

=1-cos²A +(sin3A/sinA)+cos²A-1

=sin3A/sinA

= open sin3A as (3sinA-4sin³A)

= (3sinA-4sin³A)/sinA

=again split terms

= then, (3sinA/ sinA)-(4sin³A/sinA)

=3-4sin²A ....ans...

i think this will helpful to u

ruthika18: but ans should be equal to2

ruthika18: sorry 3

puchkii: wait isn't sin A is divided by whole term of sin

puchkii: and cosA is divided by whole term of cos

ruthika18: wait I will see it

puchkii: ok

ruthika18: I am not getting it

puchkii: then how we will get the crrct ans

ruthika18: don't no

puchkii: ok I'll try to solve it

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