(sin^3A +sin3A/sinA) +(cos^3A-cosA/cosA)=
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first split all the terms..
=(sin³A/sinA )+(sin3A/sinA)+(cos³A/cosA)- (cosA/cosA)
=sin²A + (sin3A /sinA) + cos²A -1
=now.open sin² A as (1-cos²A)
then,
=1-cos²A +(sin3A/sinA)+cos²A-1
=sin3A/sinA
= open sin3A as (3sinA-4sin³A)
= (3sinA-4sin³A)/sinA
=again split terms
= then, (3sinA/ sinA)-(4sin³A/sinA)
=3-4sin²A ....ans...
i think this will helpful to u
ruthika18:
but ans should be equal to2
sorry 3
wait isn't sin A is divided by whole term of sin
and cosA is divided by whole term of cos
wait I will see it
ok
I am not getting it
then how we will get the crrct ans
don't no
ok I'll try to solve it
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