If x^2+ 1/x^2=7 then find 3x^2-3/x^2
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5
Answer:
9√5
Step-by-step explanation:
We know that
( a - b )² = ( a + b )² - 4ab
=> ( x² - 1/x² )² = ( x² + 1/x² )² - 4( x² )( 1/x² )
=> ( x² - 1/x² )² = 7² - 4
=> ( x² - 1/x² )² = 49 - 4
=> ( x² - 1/x² )² = 45
=> x² - 1/x² = √45 = √9 × √5 = 3√5
3x² - 3/x²
= 3( x² - 1/x² )
= 3( 3√5 )
= 9√5
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