if x^2+1/x=82/9 then x^3 - 1/x^3 find the value .
saifaashimpdy176:
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x^2 +1/x^2 =83, => (x+1/x)^2 -2x.1/x =83
or, (x+1/x)^2 = 83+2 =85
or, (x+1/x) = ±√(85)
Now, x^3 + 1/x^3= (x+1/x)^3 -3*x*1/x(x+1/x)
=> (±√85)^3 - 3*(±√85) = 82√85 , - 82√85
or, (x+1/x)^2 = 83+2 =85
or, (x+1/x) = ±√(85)
Now, x^3 + 1/x^3= (x+1/x)^3 -3*x*1/x(x+1/x)
=> (±√85)^3 - 3*(±√85) = 82√85 , - 82√85
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