Question

If x=2+2⅔+2⅓
Show that x³-6x²+6x-2=0

Answer 1

hey mate

here is your solution...

=>x=2+2⅔+2⅓

=>x-2=2⅔+2⅓. ......(equ 1)

cubing both sides

=>(x-2)³=(2⅔+2⅓)³

=>x³-8-3.2x(x-2) = (2⅔)³+(2⅓)³+3.2⅔.2⅓(2⅔+2⅓)

=>x³-8-6x(x-2) = (2)²+(2)¹+3.2^(⅔+⅓)(2⅔+2⅓)

=>x³-8-6x(x-2) = 4+2+3.2¹(2⅔+2⅓)

=>x³-8-6x²+12=6+6(x-2). ..(from equ 1.)

=>x³-6x²+4=6+6x-12

=>x³-6x²-6x-2=0

(... proved...)

Answer 2

you have a teacher then let him know and let you know how to solve it