Question

if x^2+4y^2+9z^2-4xy-12yz+6xz=0,
a) x=2y-3z
b)x=y-3z
c) 2x=y-3z
d) x=3y-3z​

Answer 1

Answer:

a) x=2y-3z

Step-by-step explanation:

x²+4y²+9z²-4xy-12yz+6xz=0

=> x²+4y²+9z²+2(-2xy-6yz+3xz)=0

=> (x-2y+3z)²=0

=> x-2y+3z =0

=> x=2y-3z (ans)

hence option a will be the answer..

Answer 2

hope it's helpful

refer to attachment