if x=-2 & x square + y square + 3 x y = - 5 then find y
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the value of y is 3.
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y=3
{-2}^2 +Y^2 +{3×(-2)×Y}=-5
4+Y^2-6Y= -5
-Y{-Y + 6}= - 9
Y{6-Y}= 9
by hit and trial we get Y=3
{-2}^2 +Y^2 +{3×(-2)×Y}=-5
4+Y^2-6Y= -5
-Y{-Y + 6}= - 9
Y{6-Y}= 9
by hit and trial we get Y=3
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