If x-2 is a factor of p(x)=x^3-2ax^2+ax-1 find the value of a
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Answered by
17
x - 2 is factor of p ( x )
x = 2 will also the factor of p ( x )
When we put value of x in p ( x ) we get Zero.
x³ - 2ax² + ax - 1 = 0
8 - 8a + 2a - 1 = 0
7 - 6a = 0
6a = 7
a = 7/6
x = 2 will also the factor of p ( x )
When we put value of x in p ( x ) we get Zero.
x³ - 2ax² + ax - 1 = 0
8 - 8a + 2a - 1 = 0
7 - 6a = 0
6a = 7
a = 7/6
nikki176:
Thank u
Answered by
3
x-2=0
x=2
p(2)=2^3+-2a*2+2a-1
since it is a factor so it has 0 remainder
so
0=8-4a+2a-1
0 =7-2a
a=3.5
x=2
p(2)=2^3+-2a*2+2a-1
since it is a factor so it has 0 remainder
so
0=8-4a+2a-1
0 =7-2a
a=3.5
Thank u
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