If (x − 2) is a factor of x2−ax+4 , then the value of 'a' is
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nCorrect option is
C
132
∘
Through O draw a line EOF parallel to AB
now EF || AB and CD||AB
∵ AB || EF and AO is a transversal
we have
∠AOF+∠OAB=180
∘
∠AOF+108
∘
=180
∘
∠AOF=72
∘
∵ EF|| CD and OC is transversal
so
∠COF+∠OCD=180
∘
∠COF+120
∘
=180
∘
∠COF=60
∘
∴∠AOC=∠AOF+∠COF
=72
∘
+60
∘
=132
∘
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