if x+2 is factor of x3+ 2ax2+ax-1 then the value of a is.
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Step-by-step explanation:
use factor theorem as x+2 is factor of
x³-2ax²+16 so put x = -2 and equate the equation to 0
so putting x = -2
(-2)³-2a(-2)²+16 =0
-8-8a+16=0
-8a = -8
a = 8/8= 1
So,
a = 1
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