Question

If (x-2) isva factor of x³-mx²+10x-20 then find the value of m​

Answer 1

Answer:

m=2

Step-by-step explanation:

f(x)=x3-mx2+10x-20

by factor theorem ,

if (x-2) is factor of f(x),

f(2)=0

->8-4m+20-20=0

->4m=8

->m=2

Answer 2

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As x - 2 is factor which means x - 2 = 0

x = 2

Putting x = 2 in x³ - mx² + 10x - 20

(2)³ - (2)²×m + 10 × 2 - 20 = 0

8 - 4m + 20 - 20 = 0

8 - 4m = 0

- 4m = - 8

m = $\frac{8}{4}$

m = 2