Question

if x^2 + y^2=25 then find dy/dx​

Answer 1

Answer:

${x}^{2} + {y}^{2} = 25 \\ = > {y}^{2} = 25 - {x}^{2} \\ on \: differentiating \: both \: sides \: we \: get.. \\ = > 2y\frac{dy}{dx} = 0 - 2x \\ = > \frac{dy}{dx} = \frac{ - 2x}{2y} \\ hence \: \frac{dy}{dx} = \frac{ - x}{y}$