If x=-2 y= 6 is a solution of eq. 3ax +2ay =6 then find the value of b from2(a-1) + 2(3b - 4 ) = 4
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if x and y are the soln of the eqn then substituting the values of x and y
3a(-2)+2a(6)=6
-6a+12a=6
6a=6
a=1
now looking at the second eqn where we have to find the value of b.
we substitute the value of a in it
2(1-1)+2(3b-4)=4
2(0)+6b-8=4
6b-8=4
6b=12
b=2
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