If x = 3 - 2√2, find the value of √x + 1 ÷√x
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Given x = 3 – 2√2
⇒ x = 2 + 1 – 2√2
⇒ x = (√2)2 + 12 – 2 × √2 × 1
⇒ x = (√2 – 1 )2
∴ √x = (√2 – 1 )
Now consider, (1/√x) = 1/(√2 – 1 )
Multiply and divide with (√2 + 1 ), we get
(1/√x) = (√2 + 1 )/[(√2 – 1 )(√2 + 1 )]
= (√2 + 1 )/[2 – 1]
∴ (1/√x) = (√2 + 1 )
√x + (1/√x) = (√2 – 1) + (√2 + 1) = 2√2
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⇒ x = 2 + 1 – 2√2
⇒ x = (√2)2 + 12 – 2 × √2 × 1
⇒ x = (√2 – 1 )2
∴ √x = (√2 – 1 )
Now consider, (1/√x) = 1/(√2 – 1 )
Multiply and divide with (√2 + 1 ), we get
(1/√x) = (√2 + 1 )/[(√2 – 1 )(√2 + 1 )]
= (√2 + 1 )/[2 – 1]
∴ (1/√x) = (√2 + 1 )
√x + (1/√x) = (√2 – 1) + (√2 + 1) = 2√2
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Anonymous:
ty bro
ur answer is wrong
is it?
hmm....n u marked him brainliest...unfair!!
sorry at first the answer made sense but when I read yours I understood it was wrong.
^_^
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