if x=3+2√2,find value of √x-1/√x
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x=3+2√2
1/x=1/(3+2√2)
=1/(3+2√2)*(3-2√2)/(3-2√2)
=(3-2√2)/9-8
=(3-2√2)
1/x=(3-2√2) adding x
x+(1/x)=(3-2√2)+(3+2√2)
x+(1/x)=6
x+(1/x)=2+4
x+(1/x)-2=4
(√x-1/√x)^2=4
√x-1/√x=+2,-2
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