If x = 3+2√2 , then find the value of x³+1/x³
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Solution :-
Given : x = 3 + 2√2
To find : x³ + 1/x³
1/x = 1/(3 + 2√2)
On rationalizing :
= 1/(3 + 2√2) × (3 - 2√2) /(3 - 2√2)
= 3 - 2√2 / 9 - 8
= 3 - 2√2
x³ = (3 + 2√2)³
By using identity (a + b)³
= 3³ + (2√2)³ + 3 × 3 × 2√2 (3 + 2√2)
= 27 + 16√2 + (18√2 × 3) + (18√2 × 2√2)
= 27 + 16√2 + 54√2 + 72
= 99 + 70√2
1/x³ = (3 - 2√2)³
By using identity (a - b)³
= 3³ - (2√2)³ - 3 × 3 × 2√2 (3 - 2√2)
= 27 - 16√2 - (18√2 × 3) + (18√2 × 2√2)
= 27 - 16√2 - 54√2 + 72
= 99 - 70√2
Now,
x³ + 1/x³ = (99 + 70√2) + (99 - 70√2)
= 99 + 70√2 + 99 - 70√2
= 198
Hence,
198 is the required answer.
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