Question

If x=3+2√2 then x^6+x^4+x^1+1/x^3=?​
Plz answer them I'ill mark u as brainlist don't try to spam it ok.

Answer 1

Answer:

draw a line segment of length 5.4 CM draw its perpendicular bisector of angle bataiye

Answer 2

Answer:

$218-10\sqrt 2$

Step-by-step explanation:

$\frac{x^6}{x^3}+\frac{x^4}{x^3}+\frac{x}{x^3}+\frac{1}{x^3}$

$x^3+x+\frac {1}{x^2}+\frac {1}{x^3}$

$= (3+2\sqrt 2)^3+(3+2\sqrt 2)+\frac {1}{(3+2\sqrt 2)^2}+\frac{1}{(3+2\sqrt 2) ^3}$

$=99+70\sqrt 2+3+2\sqrt 2 + \frac {17-12\sqrt 2}{289-288}+\frac {99-70\sqrt 2}{9801-9800}$

$=99+3+2\sqrt 2+17-12\sqrt 2+99$

$= 218-10\sqrt 2$